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Fix ambiguity in stringification

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Happening when using clang and templated operators, clang cannot decide
between the operator provided by ReusableStringStream and the one provided
by the value value as both are templates. This is easily solved by calling
the operator<< through the member syntax.

Fixes #1285
This commit is contained in:
Julien Nitard 2018-05-30 21:32:59 -05:00 • committed by Martin Hořeňovský
parent 021fcee636
commit 7be8a41adf
7 changed files with 54 additions and 8 deletions
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13
projects/SelfTest/UsageTests/ToStringWhich.tests.cpp
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@ -20,6 +20,7 @@ struct has_operator { };
struct has_maker {};
struct has_maker_and_operator {};
struct has_neither {};
struct has_template_operator {};
std::ostream& operator<<(std::ostream& os, const has_operator&) {
os << "operator<<( has_operator )";
@ -31,6 +32,12 @@ std::ostream& operator<<(std::ostream& os, const has_maker_and_operator&) {
return os;
}
template <typename StreamT>
StreamT& operator<<(StreamT& os, const has_template_operator&) {
os << "operator<<( has_template_operator )";
return os;
}
namespace Catch {
template<>
struct StringMaker<has_maker> {
@ -69,6 +76,12 @@ TEST_CASE("stringify( has_neither )", "[toString]") {
REQUIRE( ::Catch::Detail::stringify(item) == "{ !!! }" );
}
// Call the templated operator
TEST_CASE( "stringify( has_template_operator )", "[toString]" ) {
has_template_operator item;
REQUIRE( ::Catch::Detail::stringify( item ) == "operator<<( has_template_operator )" );
}
// Vectors...