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Make StringRef's operator std::string explicit

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This way it is explicit when there is a `StringRef` -> `std::string`
conversion and makes it easier to look for allocations that could
be avoided.

Doing this has already removed one allocation per registered test
case, as there was a completely pointless `StringRef` -> `std::string`
conversion when parsing tags of a test case.
This commit is contained in:
Martin Hořeňovský 2019-09-08 14:49:40 +02:00
parent 14362533bb
commit 7b865daccc
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GPG key ID: DE48307B8B0D381A
13 changed files with 23 additions and 67 deletions
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7
projects/SelfTest/IntrospectiveTests/String.tests.cpp
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@ -142,11 +142,6 @@ TEST_CASE( "StringRef", "[Strings][StringRef]" ) {
SECTION( "to std::string" ) {
StringRef sr = "a stringref";
SECTION( "implicitly constructed" ) {
std::string stdStr = sr;
REQUIRE( stdStr == "a stringref" );
REQUIRE( stdStr.size() == sr.size() );
}
SECTION( "explicitly constructed" ) {
std::string stdStr( sr );
REQUIRE( stdStr == "a stringref" );
@ -154,7 +149,7 @@ TEST_CASE( "StringRef", "[Strings][StringRef]" ) {
}
SECTION( "assigned" ) {
std::string stdStr;
stdStr = sr;
stdStr = static_cast<std::string>(sr);
REQUIRE( stdStr == "a stringref" );
REQUIRE( stdStr.size() == sr.size() );
}